Prediction (out of sample)

[1]:
%matplotlib inline
[2]:
import numpy as np
import matplotlib.pyplot as plt

import statsmodels.api as sm

plt.rc("figure", figsize=(16, 8))
plt.rc("font", size=14)

Artificial data

[3]:
nsample = 50
sig = 0.25
x1 = np.linspace(0, 20, nsample)
X = np.column_stack((x1, np.sin(x1), (x1 - 5) ** 2))
X = sm.add_constant(X)
beta = [5.0, 0.5, 0.5, -0.02]
y_true = np.dot(X, beta)
y = y_true + sig * np.random.normal(size=nsample)

Estimation

[4]:
olsmod = sm.OLS(y, X)
olsres = olsmod.fit()
print(olsres.summary())
                            OLS Regression Results
==============================================================================
Dep. Variable:                      y   R-squared:                       0.980
Model:                            OLS   Adj. R-squared:                  0.979
Method:                 Least Squares   F-statistic:                     764.5
Date:                Thu, 12 Mar 2026   Prob (F-statistic):           3.09e-39
Time:                        16:11:17   Log-Likelihood:                -4.0099
No. Observations:                  50   AIC:                             16.02
Df Residuals:                      46   BIC:                             23.67
Df Model:                           3
Covariance Type:            nonrobust
==============================================================================
                 coef    std err          t      P>|t|      [0.025      0.975]
------------------------------------------------------------------------------
const          4.9305      0.093     52.923      0.000       4.743       5.118
x1             0.5143      0.014     35.793      0.000       0.485       0.543
x2             0.5335      0.056      9.446      0.000       0.420       0.647
x3            -0.0216      0.001    -17.112      0.000      -0.024      -0.019
==============================================================================
Omnibus:                        0.523   Durbin-Watson:                   1.922
Prob(Omnibus):                  0.770   Jarque-Bera (JB):                0.582
Skew:                           0.225   Prob(JB):                        0.747
Kurtosis:                       2.722   Cond. No.                         221.
==============================================================================

Notes:
[1] Standard Errors assume that the covariance matrix of the errors is correctly specified.

In-sample prediction

[5]:
ypred = olsres.predict(X)
print(ypred)
[ 4.39083819  4.8970421   5.36125956  5.7544136   6.05792096  6.26674532
  6.39022468  6.45053721  6.47905741  6.51120137  6.58060803  6.71361236
  6.92491864  7.21518455  7.57091315  7.96667035  8.3692637   8.7431958
  9.05649639  9.28597503  9.42103119  9.46539589  9.43651869  9.36270084
  9.27844536  9.21878839  9.2135428   9.28240003  9.43169483  9.65336453
  9.92627362 10.21968636 10.4983165  10.72812474 10.88191128 10.94378469
 10.91177281 10.79814676 10.62740487 10.43224763 10.2482051  10.10779946
 10.03520165 10.0422602  10.12655453 10.27179263 10.45048784 10.62847477
 10.7705226  10.84612345]

Create a new sample of explanatory variables Xnew, predict and plot

[6]:
x1n = np.linspace(20.5, 25, 10)
Xnew = np.column_stack((x1n, np.sin(x1n), (x1n - 5) ** 2))
Xnew = sm.add_constant(Xnew)
ynewpred = olsres.predict(Xnew)  # predict out of sample
print(ynewpred)
[10.81880584 10.65048132 10.36207295 10.00126177  9.63081278  9.3132079
  9.09534822  8.99707096  9.00629266  9.08196758]

Plot comparison

[7]:
import matplotlib.pyplot as plt

fig, ax = plt.subplots()
ax.plot(x1, y, "o", label="Data")
ax.plot(x1, y_true, "b-", label="True")
ax.plot(np.hstack((x1, x1n)), np.hstack((ypred, ynewpred)), "r", label="OLS prediction")
ax.legend(loc="best")
[7]:
<matplotlib.legend.Legend at 0x7fe88f75e020>
../../../_images/examples_notebooks_generated_predict_12_1.png

Predicting with Formulas

Using formulas can make both estimation and prediction a lot easier

[8]:
from statsmodels.formula.api import ols

data = {"x1": x1, "y": y}

res = ols("y ~ x1 + np.sin(x1) + I((x1-5)**2)", data=data).fit()

We use the I to indicate use of the Identity transform. Ie., we do not want any expansion magic from using **2

[9]:
res.params
[9]:
Intercept           4.930540
x1                  0.514291
np.sin(x1)          0.533531
I((x1 - 5) ** 2)   -0.021588
dtype: float64

Now we only have to pass the single variable and we get the transformed right-hand side variables automatically

[10]:
res.predict(exog=dict(x1=x1n))
[10]:
0    10.818806
1    10.650481
2    10.362073
3    10.001262
4     9.630813
5     9.313208
6     9.095348
7     8.997071
8     9.006293
9     9.081968
dtype: float64