Prediction (out of sample)#

[1]:
%matplotlib inline
[2]:
import matplotlib.pyplot as plt
import numpy as np

import statsmodels.api as sm

plt.rc("figure", figsize=(16, 8))
plt.rc("font", size=14)

Artificial data#

[3]:
nsample = 50
sig = 0.25
x1 = np.linspace(0, 20, nsample)
X = np.column_stack((x1, np.sin(x1), (x1 - 5) ** 2))
X = sm.add_constant(X)
beta = [5.0, 0.5, 0.5, -0.02]
y_true = np.dot(X, beta)
y = y_true + sig * np.random.normal(size=nsample)

Estimation#

[4]:
olsmod = sm.OLS(y, X)
olsres = olsmod.fit()
print(olsres.summary())
                            OLS Regression Results
==============================================================================
Dep. Variable:                      y   R-squared:                       0.984
Model:                            OLS   Adj. R-squared:                  0.983
Method:                 Least Squares   F-statistic:                     923.2
Date:                Wed, 09 Sep 2026   Prob (F-statistic):           4.37e-41
Time:                        05:30:58   Log-Likelihood:                 1.0739
No. Observations:                  50   AIC:                             5.852
Df Residuals:                      46   BIC:                             13.50
Df Model:                           3
Covariance Type:            nonrobust
==============================================================================
                 coef    std err          t      P>|t|      [0.025      0.975]
------------------------------------------------------------------------------
const          5.0381      0.084     59.865      0.000       4.869       5.207
x1             0.4870      0.013     37.518      0.000       0.461       0.513
x2             0.4937      0.051      9.675      0.000       0.391       0.596
x3            -0.0186      0.001    -16.295      0.000      -0.021      -0.016
==============================================================================
Omnibus:                        0.272   Durbin-Watson:                   1.752
Prob(Omnibus):                  0.873   Jarque-Bera (JB):                0.105
Skew:                           0.112   Prob(JB):                        0.949
Kurtosis:                       2.975   Cond. No.                         221.
==============================================================================

Notes:
[1] Standard Errors assume that the covariance matrix of the errors is correctly specified.

In-sample prediction#

[5]:
ypred = olsres.predict(X)
print(ypred)
[ 4.57385062  5.04125498  5.47027837  5.83401646  6.11527457  6.30939267
  6.42501103  6.48265065  6.51134172  6.54385402  6.61131298  6.7380858
  6.93777805  7.21099828  7.54525803  7.91702367  8.2955829   8.6480907
  8.94496565  9.1647501   9.2976356   9.34707438  9.32921219  9.27023555
  9.20206944  9.15713207  9.16300867  9.23791934  9.38772549  9.60496689
  9.8700873  10.15464755 10.425998   10.65264278 10.80941449 10.88160909
 10.8674018  10.77814683 10.63651198 10.47275434 10.31974916 10.20758854
 10.15863736 10.18385882 10.28101321 10.43502587 10.62046394 10.80571489
 10.95818038 11.04963207]

Create a new sample of explanatory variables Xnew, predict and plot#

[6]:
x1n = np.linspace(20.5, 25, 10)
Xnew = np.column_stack((x1n, np.sin(x1n), (x1n - 5) ** 2))
Xnew = sm.add_constant(Xnew)
ynewpred = olsres.predict(Xnew)  # predict out of sample
print(ynewpred)
[11.05133099 10.92326175 10.68478404 10.38001614 10.06703322  9.80364853
  9.63325869  9.57421867  9.61534789  9.71866757]

Plot comparison#

[7]:
import matplotlib.pyplot as plt

fig, ax = plt.subplots()
ax.plot(x1, y, "o", label="Data")
ax.plot(x1, y_true, "b-", label="True")
ax.plot(np.hstack((x1, x1n)), np.hstack((ypred, ynewpred)), "r", label="OLS prediction")
ax.legend(loc="best")
[7]:
<matplotlib.legend.Legend at 0x7f4994979010>
../../../_images/examples_notebooks_generated_predict_12_1.png

Predicting with Formulas#

Using formulas can make both estimation and prediction a lot easier

[8]:
from statsmodels.formula.api import ols

data = {"x1": x1, "y": y}

res = ols("y ~ x1 + np.sin(x1) + I((x1-5)**2)", data=data).fit()

We use the I to indicate use of the Identity transform. Ie., we do not want any expansion magic from using **2

[9]:
res.params
[9]:
Intercept           5.038093
x1                  0.486951
np.sin(x1)          0.493665
I((x1 - 5) ** 2)   -0.018570
dtype: float64

Now we only have to pass the single variable and we get the transformed right-hand side variables automatically

[10]:
res.predict(exog=dict(x1=x1n))
[10]:
0    11.051331
1    10.923262
2    10.684784
3    10.380016
4    10.067033
5     9.803649
6     9.633259
7     9.574219
8     9.615348
9     9.718668
dtype: float64